Question

S(x) = p x² + (p-2)x + 2. If '2' is the zero of this polynomial, what is the value of 'p'? *

1 point

(a) -1

(b) 1/3

(c) -1/3

(d) +1

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Answer 1

Step-by-step explanation:

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Answer 2

The value of p is 1/3.

S(x) = p x² + (p-2)x + 2

substitute x=2 in S(x)

s(x) = p(2)²+ (p-2)2 + 2

= 4p +2p -4 + 2

= 6p - 2

2 = 6p

2/6 = p

p = 1/3

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