Question

S(x) = px2+(p-2)x +2. If 2 is the zero of this polynomial,what is the value of p__

Answer 1

Step-by-step explanation:

The value of p is p=\frac{1}{4}p=

4

1

.

Step-by-step explanation:

Given : S(x)=px^2+(p-2)x+2S(x)=px

2

+(p−2)x+2 .If 2 is the zero of this polynomial.

To find : The values of p ?

Solution :

The polynomial S(x)=px^2+(p-2)x+2=0S(x)=px

2

+(p−2)x+2=0 .

Zero of polynomial is 2 i.e. substitute x=2,

p(2)^2+(p-2)(2)+2=0p(2)

2

+(p−2)(2)+2=0

4p+4p-4+2=04p+4p−4+2=0

8p=28p=2

p=\frac{2}{8}p=

8

2

p=\frac{1}{4}p=

4

1

Therefore, the value of p is p=\frac{1}{4}p=

4

1

.

#Learn more

If the sum of the zeroes of the quadratic polynomial kx2-3x+5 is 3, find the value of k

Answer 2

Step-by-step explanation:

since 2 is the zero of this polynomial substitute 2 in place of x , p=3.