Question

S(x) = px2+(p-2)x +2. If  2 is the zero of this polynomial,what is the value of p

Answer 1

The value of p is $p=\frac{1}{4}$.

Step-by-step explanation:

Given : $S(x)=px^2+(p-2)x+2$.If  2 is the zero of this polynomial.

To find : The values of p ?

Solution :

The polynomial $S(x)=px^2+(p-2)x+2=0$.

Zero of polynomial is 2 i.e. substitute x=2,

$p(2)^2+(p-2)(2)+2=0$

$4p+4p-4+2=0$  

$8p=2$

$p=\frac{2}{8}$

$p=\frac{1}{4}$

Therefore, the value of p is $p=\frac{1}{4}$.

#Learn more

If the sum of the zeroes of the quadratic polynomial kx2-3x+5 is 3, find the value of k

https://brainly.in/question/3266108

Answer 2

Hope you understand the answer

Answer is given in the page above