Question

ʜᴀʀᴅ ǫᴜᴇsᴛɪᴏɴ :-

⭐ ɪғ ᴘ(x) ɪs 3 . ᴛʜᴇɴ ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ
(1) 3x^3 + 4x^2 + 7x - 8

ɴᴏ sᴘᴀᴍ , ɴᴏ ᴄᴏᴘʏ ❌❌
ɴᴇᴇᴅ ᴡᴇʟʟ ᴇxᴘʟᴀɪɴᴇᴅ ᴀɴsᴡᴇʀ ✅✅​

Answer 1

$\cal{P(x) = {3x}^{3} + {4x}^{2} + 7x - 8}$

Putting $\sf{x = 3\:in\:P(x)}$

‎

$\cal{P(3) = {[3(3)]}^{3} + {[4(3)]}^{2} + 7(3) - 8}$

$\cal{P(3) = {9}^{3} + {12}^{2} + 21 - 8}$

$\cal{P(3) = 729 + 144 + 21 - 8}$

$\cal{P(3) = 894 - 8}$

$\large{\underline{\underline{\red{\cal{P(3) = 886}}}}}$

Answer 2

question - ɪғ ᴘ(x) ɪs 3 . ᴛʜᴇɴ ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ

(1) 3x^3 + 4x^2 + 7x - 8

answer - Let p(x) =3x3 – 4x2 + 7x – 5

At x= 3, p(3) = 3(3)3 – 4(3)2 + 7(3) – 5

= 3×27-4×9 + 21-5 = 81-36+21-5 P( 3) =61

At x = -3, p(-3)= 3(-3)3 – 4(-3)2 + 7(-3)- 5

= 3(-27)-4×9-21-5 = -81-36-21-5 = -143 p(-3) = -143

Hence, the value of the given polynomial at x = 3 and x = -3 are 61 and -143, respectively

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$natasha \: \: \: singhania$