ʜʟᴏ ғʀɴᴅs ❤
ᴇxᴘʟᴀɪɴ ɴᴜᴄʟᴇᴀʀ ᴅᴇɴsɪᴛʏ. ʙʀɪᴇғʟʏ. ᴡɪᴛʜ ɪᴛs ᴅᴇʀɪᴠᴀᴛɪᴏɴ.
ɴᴏ sᴘᴀᴍ ❌
ɴᴏ ᴄᴏᴘʏ ᴘᴀsᴛᴇ❌
Answers
Answer:
Density of nuclear matter is the ratio of mass of nucleus and its volume.
Density of nuclear matter is the ratio of mass of nucleus and its volume.
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = =
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = =
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus
Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus = 2.98 X 1017 kg/m3
The ratio of mass per unit volume is called density.
The ratio of mass per unit volume inside the nucleus is called nuclear density.
As we know, the nucleus is spherical in shape so its volume must be very small as its radius is of order of 10-14. This leads to tremendous high nuclear density of nucleus.
Density of Nuclear Matter
The nuclear density for a typical nucleus can be approximately calculated from the size of the nucleus and from its mass. Typical nuclear radii are of the order 10−14 m.
Assuming spherical shape, nuclear radii can be calculated according to following formula:
r = r0 . A1/3
where r0 = 1.2 x 10-15 m = 1.2 fm
For example, natural uranium consists primarily of isotope 238U (99.28%), therefore the atomic mass of uranium element is close to the atomic mass of 238U isotope (238.03u).
Its radius of this nucleus will be:
r = r0 . A1/3 = 7.44 fm.
Assuming it is spherical, its volume will be:
V = 4πr3/3 = 1.73 x 10-42 m3.