Biology, asked by AmanKaur01, 2 months ago

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Answers

Answered by shubhangi3757
2

Answer:

Density of nuclear matter is the ratio of mass of nucleus and its volume.

Density of nuclear matter is the ratio of mass of nucleus and its volume.

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = =

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = =

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus

Density of nuclear matter is the ratio of mass of nucleus and its volume. Mass of nucleus = mA Volume of nucleus = = Density of Nuclear matter = mass of nucleus / volume of nucleus = 2.98 X 1017 kg/m3

Answered by Anonymous
2

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The ratio of mass per unit volume is called density.

The ratio of mass per unit volume inside the nucleus is called nuclear density.

As we know, the nucleus is spherical in shape so its volume must be very small as its radius is of order of 10-14. This leads to tremendous high nuclear density of nucleus.

Density of Nuclear Matter

The nuclear density for a typical nucleus can be approximately calculated from the size of the nucleus and from its mass. Typical nuclear radii are of the order 10−14 m.

Assuming spherical shape, nuclear radii can be calculated according to following formula:

r = r0 . A1/3

where r0 = 1.2 x 10-15 m = 1.2 fm

For example, natural uranium consists primarily of isotope 238U (99.28%), therefore the atomic mass of uranium element is close to the atomic mass of 238U isotope (238.03u).

Its radius of this nucleus will be:

r = r0 . A1/3 = 7.44 fm.

Assuming it is spherical, its volume will be:

V = 4πr3/3 = 1.73 x 10-42 m3.

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