Question

ʜᴏᴡ ᴛᴏ ᴍᴀᴋᴇ ᴛᴀʙʟᴇs ɪɴ ʟᴀᴛᴇx ᴄᴏᴅɪɴɢ ʟɪᴋᴇ ᴛʀɪɢᴏɴᴏᴍᴇᴛʀʏ ᴠᴀʟᴜᴇ ᴛᴀʙʟᴇ? ᴇxᴘʟᴀɪɴ ɪɴ ʙʀɪᴇғ ᴍᴀɴɴᴇʀ.

sᴘᴀᴍᴍᴇʀs sᴛᴀʏ ᴀᴡᴀʏ..​

Answer 1

Step-by-step explanation: 3g3geherhej566uh+9283 Mark me as a #################

Answer 2

"$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\red{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}$