Question

s years ago a man was 7 times as old as
his sons years from how he will be 3
times as old as his
his son. find their present age​

Answer 1

Answer:

Step-by-step explanation:

letfather's age = x

son's age = y

5 years hence, age of father = x+5 

                                

age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

5 years ago, age of father = x-5 

                              

 age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10  age of son

  x = 3y +10 = 40

son age = 10 year

son age = 10 year father's age= 40 year

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