Question

s1=(1, 2, 3,....20) s2=(a,b,c,d) s3=(b, d, e, f). The number of element of( s1*s2) u s1*s3 is

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Answer 1

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Answer 2

Step-by-step explanation:

Step-by-step explanation:

Given If S1 = {1, 2, 3,...., 20}, S2 ={a, b, c, d}, S3 = {b, d, e, f}. The number of elements of (S1 x S2 ) intersection (S1 x S3) is

Now the elements of S1 are S1 = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}

The elements of S2 are S2 = {a,b,c,d}

The elements of S3 are S3 = {b,d,e,f}  

So the elements in S1 is 20 and elements in S2 is 4 and elements in S3 is also 4

Now we have S1 x S2 = 20 x 4 = 80

                    So S1 x S3 = 20 x 4 = 80

The common elements in S2 and S3 are b and d = 20 x 2 = 40

         Therefore number of elements will be the intersection

= 80 + 80 – 40 = 120

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