Math, asked by adilkk43, 4 months ago

S1 = 100 + 101 + 102 + 103 + .....+ 999.

S3 = 100^3 + 101^3 + 102^3 + 103^3 + ....... +999^3.

S6 = 100^6 + 101^6 + 102^6 + 103^6 +..... + 999^6

What is the remainder when S1, S3, S6 are divided by 7 ??

Answers

Answered by ramlaltiwari449
1

I can't understand this question

Answered by bharmappa73
0

Answer:

s1=104

s3=104^3

s6=104^6

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