Question

S1 and S2 are the distances covered by a freely falling body in xth and yth seconds find g

Answer 1

Answer: s1=5 x=3 and s2=10 y=6

from origin s1 is 5 meters out and it takes 3 secs to get to

 

s2 is 10 meters out and takes 6 secs to get to

then logically to find distance traveled it would be s2-s1=10-5 and amount of time y-x=6-3

so 5 meters for every 3 secs

%28s2-s1%29%2F%28y-x%29=g

Explanation:

Answer 2

Answer:

     The distance covered by $g=\frac{s2-s1}{y-x}$.

Explanation:

   Hence,  s1=5 x=3 and s2=10 y=6

from the origin, s1 is 5 meters out and it takes 3 secs to get to

        s2 is 10 meters out and takes 6 secs to get to

then logically to find the distance traveled it would be s2-s1=10-5 and the amount of time y-x=6-3

       so 5 meters for every 3 secs

                             $\frac{s2-s1}{y-x} =g$