Question

S1 and S2 are two hollow concentric spheres enclosing charges Q and 3Q respectively What is the ratio of electric flux through S1 and S2? what would be the electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​

Answer 1

Given:

• Charge enclosed by the hollow spherical surface S1 = Q
• Charge enclosed by the hollow spherical surface S2 = 3Q
• The dielectric constant (k) = 3

To find:

1. The ratio of electric flux through S1 and S2
2. The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​

Solution:

• According to Gaus's law the electric flux through a surface is equal to the charge enclosed by the surface divided by ξ₀
• Flux through S1 = Q/ξ₀
• Flux through S2 = 3Q/ξ₀
• The ratio of electric flux through S1 and S2 = 1/3
• The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​ = Q/kξ₀ = Q/3ξ₀

Answer:

1. The ratio of electric flux through S1 and S2 = 1/3
2. The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​ = Q/3ξ₀

Answer 2

Given:

Charge enclosed by the hollow spherical surface S1 = Q

Charge enclosed by the hollow spherical surface S2 = 3Q

The dielectric constant (k) = 3

To find:

The ratio of electric flux through S1 and S2

The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​

Solution:

According to Gaus's law the electric flux through a surface is equal to the charge enclosed by the surface divided by ξ₀

Flux through S1 = Q/ξ₀

Flux through S2 = 3Q/ξ₀

The ratio of electric flux through S1 and S2 = 1/3

The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​ = Q/kξ₀ = Q/3ξ₀

Answer:

The ratio of electric flux through S1 and S2 = 1/3

The electric flux through S1 if air inside S1 is replaced by a medium of dielectric constant 3​ = Q/3ξ₀