Question

s1 and s2 are two square figurevs1 is smaller and length of its side is x cm . s2 is bigger square and length of its side is y cm . If it is given that x²+y²=74 and 2x²-y²=1 then the side of the bigger square is of length is

(a) 7cm
(b) 5cm
(c) 25cm
(d) 14cm​

Answer 1

Answer:

(a) 7cm

x^2 + y^2 = 74 ,

2x^2 - y^2 = 1

3x^2. = 75

x^2 = 75/3

x^2. = 25

x. =. 5

(5)^2 + y^2 = 74

y^2 = 74-25

y = 7

Answer 2

Answer:

(a)7cm

Step-by-step explanation:

Step 1

Let ,

x²+y²=74 Be equation 1

2x²-y²=1 Be equation 2

Multiply Equation 1 with -2

So equation is -2x²-2y²=-148

Add this with equation 2

-2x²-2y²=-148

    2x²-y²=1

By simplifying y=7

substitute y=7 in equation 1

So that x=5

Therefore Length of side of the bigger Square s2 is 7cm