Question

S1. Draw a line segment AB of length 8 cm and construct a line parallel to it lying 3 cm above it.
Solution​

Answer 1

A N S W E R :

Steps of Construction : 

• 1. With P and Q as centers, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ. 

• 2. Let these arcs cut each other at points R and RS 

• 3. Join RS which cuts PQ at D. Then RS=PQ. Also ∠POR=90∘.

• Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ. On measuring the lengths of PR=4cm, QR=4 cm Since PR=QR, both are 4cm each 

• ∴PR=QR.

Hope It Helps You !!! <3

Answer 2

Answer:

$\huge \pink{~} \red {A} \green {N} \blue {S} \orange {W} \pink {E} \red {R}$

S1. Draw a line segment AB of length 8 cm and construct a line parallel to it lying 3 cm above it.

Solution