S1,S2,S3,,,,,,,,S10 are speakers in a conference .if S1 addresses only after S2 , then the number of ways the speakers address is ......
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From symmetry S1 speaks before S2 in equal number of ways that S1 speaks after S2.
Total number of ways that 10 speakers can talk (ordering) = 10P10 = 10!
Answer = 10! /2.
See attached pictures for alternate methods.
Total number of ways that 10 speakers can talk (ordering) = 10P10 = 10!
Answer = 10! /2.
See attached pictures for alternate methods.
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