Question

S₁₀=50, a=0.5, find d,For the given AP, find

Answer 1

given, $S_{10}=50,a=0.5$

we know, formula $S_n=\frac{n}{2}[2a+(n-1)d]$

so, $S_10=50$
$S_10=\frac{10}{2}[2a+(10-1)d]=50$
5(2a + 9d) = 50
2a + 9d = 10
put a = 0.5,
2 × 0.5 + 9d = 10
1 +9d = 10
9d = 9 => d = 1

hence, d = 1