Math, asked by ravindrawalke27, 1 day ago

S2. Construct a APQR with PQ = 5.5 cm, QR = 6.5 cm and ZQ = 80°.
SOLUTION.​

Answers

Answered by Jiya0071
0

Step-by-step explanation:

Steps of construction :

Draw a line segment PQ of length 5 cm.

At P, draw a ray PX making 35° with PQ.

At Q, draw a ray QY making 105° with PQ.

Rays PX and QY will intersect at point R.

Triangle PQR is now constructed.

Attachments:
Answered by SurajBrainlyStarz
0

Answer:

Steps of Construction:

(i) Construct a line segment PR = 6.5 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilateral.

Similar questions