S2. Construct a APQR with PQ = 5.5 cm, QR = 6.5 cm and ZQ = 80°.
SOLUTION.
Answers
Answered by
0
Step-by-step explanation:
Steps of construction :
Draw a line segment PQ of length 5 cm.
At P, draw a ray PX making 35° with PQ.
At Q, draw a ray QY making 105° with PQ.
Rays PX and QY will intersect at point R.
Triangle PQR is now constructed.
Attachments:
Answered by
0
Answer:
Steps of Construction:
(i) Construct a line segment PR = 6.5 cm.
(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.
(iii) Now join PQ and QR.
(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.
(v) Join PS and SR.
Hence, PQRS is the required quadrilateral.
Similar questions