Question

s2-s1 =. in terms of AP ​

Answer 1

Answer:

n/2[2a + (n − 1) × d]

Step-by-step explanation:

General Form of AP are a, a + d, a + 2d, a + 3d, . . .

The nth term of AP an = a + (n – 1) × d

Sum of n terms in AP series = n/2[2a + (n − 1) × d] = s2-s1

Answer 2

Answer:

The answer is S2-S1 = a2 = second term of AP.

tep-by-step explanation:

As per the data given in the question,

We need to find S2 - S1 in terms of AP.

In this S2= sum of first 2 terms= $a1+a2$ = $a1+a1+d$

where d is the difference between consecutive terms

S1 = sum of first term = $a1$

So, $S2-S1=a1+a1+d-a1$

$S2-S1=a1 +d = a2$

∴$S2-S1=a2= second \:term \:of\: AP$

#SPJ2