Chemistry, asked by dhanotepratha, 8 months ago

s2o42negative find oxidation number of sulphur

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Answered by gargnk721

0

Answer:

3

Explanation:

2 oxidation no. of S + 4 oxidation no. of 0 = charge

2x+4(-2)=-2

X= 3

so oxidation no. s is 3

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