Question

S3)
If p(x) = x2 – 5x – 6, then find the values of p(1), p(2), p(3), p(0), p(-1), p(-2), p(-3).
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

p(x)=x^2-5x-6

p(1)=(1)^2-5(1)-6=1-5-6=-10

p(2)=(2)^2-5(2)-6=4-10-6=-12

p(3)=(3)^2-5(3)-6=9-15-6=-12

p(0)=(0)^2-5(0)-6=0-0-6=-6

p(-1)=(-1)^2-5(-1)-6=1+5-6=0

p(–2)=(-2)^2-5(-2)-6=4+10-6=8

p(-3)=(-3)^2-5(-3)-6=9+15-6= 18

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