Question

S4. The area of a trapezium is 92.4 cm’ and its height
is 5.6 cm. If one of its pafallel sides is longer than
the other by 3 cm, find the lengths of the two Parrallel sides
​

Answer 1

• Length of parallel sides is 18 cm and 15 cm.

Step-by-step explanation:

Given :-

• Area of trapezium is 92.4 cm².
• Height of trapezium is 5.6 cm.

To find :-

• Length of both parallel sides.

Solution :-

Let, one parallel side of trapezium be x cm.

And, Other parallel side be x + 3 cm. [One parallel side is longer than other]

We know,

Area of trapezium = (a + b)/2 × h

Where,

• a and b are parallel sides and h is height of parallel sides.

So, Put the values :-

⇒92.4 = (x + 3 + x)/2 × 5.6

⇒92.4/5.6 = (2x + 3)/2

⇒16.5 = (2x + 3)/2

⇒16.5 × 2 = 2x + 3

⇒33 = 2x + 3

⇒33 - 3 = 2x

⇒30 = 2x

⇒30/2 = x

⇒x = 15

Parallel sides :-

We take,

One parallel side be x. One parallel side is 15 cm.

Other parallel side be x + 3 = 15 + 3 = 18. Thus, Other parallel side is 18 cm.

Answer 2

Step-by-step explanation:

$\bf \huge \underline \red{Answer:-}$

Let the shorter side be x and longer side be x+3

$\tt{ \boxed{ \green{Area \: \: of \: \: Trapezium = \frac{1}{2} (a + b)h}}}$

$\bf \longmapsto \pink{92.4 = \frac{1}{2} \times 5.6 \times (2x + 3)}$

$\bf \longmapsto \pink{92.4 = 2.8(2x + 3)}$

$\bf \longmapsto \pink{ \frac{92.4}{2.8} = 2x + 3}$

$\bf \longmapsto \pink{33 = 2x + 3}$

$\bf \longmapsto \pink{2x = 30}$

$\bf \longmapsto \pink{x = 15}$

$\therefore \tt \red{shorter \: \: side \: = 15cm} \: \: and \: \red{longer \: \: side \: \: = 18cm}$

•°• The lengths of the two parallel sides is 15 cm and 18cm .