S7 of an AP=49, S17 of an AP =289, find S10
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Answer:
f7 = 49
f17 = 289
d = 289-49
17 - 7
= 240
10
= 24
f1 = 49 - 6*24
= -95
Sn = 10[2*-95+(10-1)*2]
2
= 5* -190 + 216
= 5*26
= 130
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