Chemistry, asked by kshitij185, 11 months ago

सोडियम, ऑक्सीजन एवं मैग्नीशियम के लिए इलेक्ट्रॉन-बिंदु संरचना लिखिए।​

Answers

Answered by tom77
35

Answer:

Sodium (Na) is (2,8,1)

Oxygen (O^2) is (2,6)

Magnesium (Mg) is (2,8,2)

Answered by Alleei
10

Answer : The electron-dot structure of sodium, oxygen and magnesium are shown below.

Explanation :

Electron-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

Element = Sodium (Na)

Atomic number = 11

Number of electrons = 11

Electronic configuration of Na = 1s^22s^22p^63s^1

The number of valence electrons in Na is, 1.

Element = Oxygen (O)

Atomic number = 8

Number of electrons = 8

Electronic configuration of O= 1s^22s^22p^4

The number of valence electrons in O is, 6.

Element = Magnesium (Mg)

Atomic number = 12

Number of electrons = 12

Electronic configuration of Mg = 1s^22s^22p^63s^2

The number of valence electrons in Mg is, 2.

The electron-dot structure of sodium, oxygen and magnesium are shown below.

Attachments:
Similar questions