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Answer:
sin(theta) = a / c csc(theta) = 1 / sin(theta) = c / a
cos(theta) = b / c sec(theta) = 1 / cos(theta) = c / b
tan(theta) = sin(theta) / cos(theta) = a / b cot(theta) = 1/ tan(theta) = b / a
Step-by-step explanation:
Identity Tan(squared)x+1=Sec(squared)x] |
1 − cos2θ. ... The first shows how we can express sin θ in terms of cos θ; the second shows how we can express cos θ in terms of sin θ. Note: sin2θ -- "sine squared theta" -- means (sin θ)2. Problem 3. A 3-4-5 triangle is right-angled.
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