Chemistry, asked by savkaremansi, 3 months ago

स्टैंडर्ड इन थे लीफ इंफॉर्मेशन ऑफ वॉटर इज - 286 केजे मॉल माइनस वन कैलकुलेट द एंथैल्पी चेंज फॉर फॉरमेशन आफ 0.01 8kg ऑफ वाटर​

Answers

Answered by bannybannyavvari
0

Answer:

The enthalpy change, for the transition of liquid water to steam, ΔHvapour is 40.8kJ mol^-1 at 373K . Calculate the entropy change for the process.

Top answer · 10 votes

The transition under consideration is: H2O(l)⟶H2O(g) We know that, ΔSvapour = ΔHvapourT given, ΔHvapour = 40.8kJ mol^-1 = 40.8 × 1000J mol^-1

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