Question

सिद्ध किजिए 3+अंडर रूट 5 एक अपरिमेय संख्या है​

Answer 1

Answer:

you can take hint from here it's same like 3+√5 only

Answer 2

$\huge\underline\mathfrak\color{red} Answer$

Let us assume that 6+√2 is rational.

That is , we can find coprimes a and b (b≠0) such that

6+√2 = a/b

√2= a/b - 6

$\sqrt{2 - \frac{a - 6b}{b} }$

Since , a and b are integers , is rational ,and so √2 is rational.

But this contradicts the fact that √2 is irrational.

So, we conclude that 6+√2 is irrational.