सिद्ध कीजिए कि-
3
(i) sin 20° sin 40° sin 60° sin 80°
16
Answers
Answered by
1
Answer:
Mark me as Brainlist
Step-by-step explanation:
sin20. sin 40. sin60. sin80
=> sin60[sin20.sin40.sin80]
=>√3/2[sin20.sin(60-20).sin(60+20)]
=>√3/2[sin 3(20)/4]
=>√3/2[sin 60/4]
=>√3/2[√3/2*4]
=>√3/2*√3/8
=3/16
Answered by
0
Answer:
=-√3/2.sin20sin(60-20)sin(60+20)
=√3/2sin20{sin^260-sin^220)
√3/2sin20{3/4-sin^220
=√3/2×(1/4)(3sin20 - 4sin^3 20)
=√3/8.sin60 (3sinA - 4sin^3A= sin3A)
=√3/8×√3/2
=3/16
Similar questions