Question

सिद्ध कीजिए कि चतुर्भुज के चारों कोणों का योग 360° होता है।

Answer 1

Step-by-step explanation:

Consider triangle ABC , we have,

∠A + ∠ABC + ∠ACB = 180º ... (1) [Using Angle sum property of Triangle]

Similarly, in triangle BDC, we have,

∠CBD + ∠D + ∠BCD = 180º ... (2) [Using Angle sum property of Triangle]

On adding (1) and (2), we get

∠A + ∠ABC + ∠ACB + ∠CBD + ∠D + ∠BCD = 180º + 180º

∠A + ∠ABC + ∠CBD + ∠D + ∠BCD + ∠ACB = 360º

∠A + ∠B + ∠D + ∠C = 360º

[Hence proved]