Question

- सिद्ध कीजिए कि किसी संहत दूरीक समष्टि का एक संवृत उपसमुच्चय संहत होता है।Prove that a closed subset of aetric space is compact​

Answer 1

Answer:

Then x ∈ F since F is closed, so F is compact. Alternatively, If {Gα ⊂ X : α ∈ I} is an open cover of F, then {Gα : α ∈ I} ∪ Fc is an open cover of X. Since X is compact, there is a finite subcover of X which also covers F, so F is compact.

Step-by-step explanation:

pls thank myy answer I u like it is useful to you

Answer 2

Step-by-step explanation:

सिद्ध कीजिए कि दूरीक समष्टि के संहत उपसमुच्चय संवृत होते हैं