Question

सिद्ध कीजिएः tan2Asec2B – sec2Atan2B =tan2A – tan2B

Answer 1

Answer:

sorry i don't know the answer

Answer 2

$\tan^2 A\sec^2 B-\sec^2A\tan^2B =\tan^2A-\tan^2B$, सिद्ध

Step-by-step explanation:

सिद्ध कीजिए, $\tan^2 A\sec^2 B-\sec^2A\tan^2B =\tan^2A-\tan^2B$

L.H.S. $=\tan^2 A\sec^2 B-\sec^2A\tan^2B$

$=\tan^2 A(1+\tan^2B )-(1+\tan^2A)\tan^2B$

त्रिकोणमितीय सूत्र का उपयोग करते हुए,

$\sec^2 A-\tan^2 A=1$

$=\tan^2 A+\tan^2 A\tan^2B-\tan^2B -\tan^2A\tan^2B$

$=\tan^2 A-\tan^2B$

= R.H.S., सिद्ध

∴ $\tan^2 A\sec^2 B-\sec^2A\tan^2B =\tan^2A-\tan^2B$, सिद्ध