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Prove that a finite, non-zero commutative rings without zero division is a field.
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First, we show that R has an identity. (Sometimes the existence of an identity is included in the definition of a ring, but you do not need it here.)
For each 0≠a∈R, consider the map
ϕa:R→R,x↦ax.
Because a is not a zero-divisor, the map ϕa is injective, thus surjective. So there is e∈R such that
a=ϕa(e)=ea.(1)
Again because the map ϕa is surjective, every b∈R is of the form
b=ϕa(xb)=axb
for some xb, so multiplying (1) by xb you find
b=eb
for all b∈R, so e is the identity.
Now use once more the fact that ϕa is surjective, to show that there is c∈R such that
ac=ϕa(c)=e,
so c is an inverse of a, a being an arbitrary non-zero element.
Step-by-step explanation:
Hope it Helps.
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