Math, asked by prernakumari916264, 3 months ago



सिद्ध करे कि 5 - 2 रूट अंडर 3 एक अपरिमेय संख्या है
5 - 2  \sqrt{3}

Answers

Answered by sunitagupta2842
0

माना 5 - 2 रूट 3 एक परिमेय संख्या है

इसीलिए a÷ b = 5 - 2 root 3

a÷ b - 5 = - 2 root 3

L.H.S

kyuki a÷b ek parimey sankhya hai

isiley a÷b -5 bhi ek parimey sankhya hai ------(1)

R.H.S

kyuki root 3 ek aparimey sankhya hai isiley - 2 root 3 bhi ek aparimey sankhya hai ------(2)

samikaran (1) aur (2) se

isiley 5 - 2 root 3 ek aparimey sankhya hai

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