Question

सिध्द कीजिए √(1-cos^2°).sec^2°=tan°

Answer 1

Here is your solution

LHS

$= \sqrt{(1 - cos° ){}^{2} \times sec {}^{2}° } \\ \\= \sqrt{sin {}^{2}° \times sec {}^{2}° } \\\\ = \sqrt{sin {}^{2} \times \frac{1}{cos {}^{2}° } } \\ \\ = \sqrt{ \frac{sin {}^{2}° }{cos {}^{2}° } } \\ \\ = \frac{sin°}{cos° } \\ = tan°$

Hence
Lhs = rhs

Note:-
sin°/cos°=tan°

Hope it helps you