सिध्द कीजिये समूह का केंद्र सदैव प्रसामान्य उपसमूह होता है
Answers
SOLUTION
TO PROVE
The centre of a group is a normal subgroup of the group
PROOF
Let G be a group
Then centre Z(G) of G is defined as
Z(G) = { x ∈ G : xg = gx for all g ∈ G }
Now Z(G) is a subgroup of G
We now prove that Z(G) is a normal subgroup of the group G
Let H = Z(G) and let a ∈ G
We have to prove that aH = Ha
Let p ∈ aH
Then p = ah for some h ∈ H
⇒ p = ha since h ∈ Z(G)
So p ∈ aH implies p ∈ Ha
Therefore aH ⊂ Ha
Similarly it can be shown that Ha ⊂ aH
Thus we get aH = Ha for all a ∈ G
∴ H = Z(G) is a normal subgroup of the group G
Hence proved
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