Question

Sabrina rode on a Ferris wheel at the state fair. The radius of the Ferris wheel was 136 feet.

What is the approximate distance Sabrina traveled in one revolution of the Ferris wheel? Use = 3.14.

Answer 1

Step-by-step explanation:

• r = 136 feet
• ferris wheel is in form of circle
• perimeter is distance travelled by Sabrina

$perimeter \: of \: circle = 2\pi \: r$

• $2(3.14) (136)$

Answer 2

The approximate distance Sabrina traveled in one revolution of the Ferris wheel is 854 feet.

Step-by-step explanation:

Given : Sabrina rode on a Ferris wheel at the state fair. The radius of the Ferris wheel was 136 feet.

To find : What is the approximate distance Sabrina traveled in one revolution of the Ferris wheel?

Solution :

Distance Sabrina traveled in one revolution of the Ferris wheel is the circumference of the wheel.

Circumference of the circle is $C=2\pi r$

Here, r is the radius r=136 feet

$C=2\times 3.14\times 136$

$C=854.08\ ft$

The approximate distance Sabrina traveled in one revolution of the Ferris wheel is 854 feet.

#Learn more

A rider boards a Ferris wheel 10 feet above ground level. The diameter of the Ferris wheel is 50 feet and the wheel completes one full rotation every 24 seconds. Which graph represents the relationship between time and height off the ground?\

https://brainly.in/question/9040157