Question

Saccharin is used as an artificial sweetening agent. The molecular formula of saccharin is carbon7hydrogen5nitrogen1oxygen3sulphur1 . 0.2 g of saccharin contains
a) how many atoms of nitrogen ?
b) how many molecules of the compound?
c) how many moles of the compound?​

Answer 1

In 1 mole Nitrogen or 28 u nitrogen there are 6.022 x 1023 atoms.

Calculate he number of moles you have by taking the Mass / molar mass. if you have 1000 grams ; then 1,000 g / 151.001 g/mol = X g moles. Then multiply by Avogadros # = 6.022140857 × 10^23 molecules per g mole. The result is the # of molecules of MnSO4.

One mole (abbreviated mol) is equal to 6.022×1023 molecular entities (Avogadro's number), and each element has a different molar mass depending on the weight of 6.022×1023 of its atoms (1 mole). The molar mass of any element can be determined by finding the atomic mass of the element on the periodic table.