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To make a toy hut 3m 25cm tarpaulin is needed. Out of 50 m tarpaulin, how many such toy huts
can be made and how much tarpaulin will remain?
Answers
Answer:
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Step-by-step explanation:
_____?
GiveN :
A conical tent of diameter 7m and height 3m is to be maid by a tarpaulin.
To FiNd :
How much tarpaulin of width 1m is required for the tent.
ANswer :
50.71 m of tarpaulin is required for the tent.
SolutioN :
The diameter of conical tent = 7m
⇒ Radius of conical tent = 7/2 = 3.5 m
⇒ Height of tent = 3 m
Therefore,
⇒ Slant height, l = √[(3.5)² + (3)²]
⇒ l = √[12.25 + 9]
⇒ l = √[21.25]
⇒ l = 4.61 m
Now, the tarpaulin is the CSA of the tent.
⇒ CSA of cone = πrl
⇒ CSA of tent = 22/7 × 3.5× 4.61
⇒ CSA of tent = 50.71 m²
Now,
⇒ Area of tarpaulin materials = CSA of the tent
⇒ Length × 1 = 50.71
⇒ Length = 50.71/1
⇒ Length = 50.71 m
∴Hence, 50.71 m of tarpaulin is required for the tent.
Step-by-step explanation:
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