Question

Sachin and Ajay are sitting at a
distance 2 meter from each other
Their masses re 50 kg and 75 kg
respecteively what is the gravitinal
force betwin them​

Answer 1

Answer:

Given : r = 1 m, m1 = 75 kg, m2 = 80 kg

and G = 6.67 x 10 -11 Nm2/kg2

According to Newton’s law

                                    `F  = (Gm_1m_2)/(r^2)`

                                   `F=(6.67 xx 10^(-11) xx 75 xx80)/1^2 n`

                                  ` = 4.002 xx 10^-7 N`

The gravitational force between Mahendra and Virat is 4.002 x 10-7 N

MARK AS BRAINLIST !!!