Math, asked by rajninegi74, 11 months ago

sachin and Rahul were playing a game, Sachin asked Rahul to guess a two digit number such that sum of its digits bis 11(1) what are the possible numbers he has guessed? (2) what is the probability that Rahul guessed a number that is divisible by 4.​

Answers

Answered by diyaverma2003
1

Answer:

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Answered by santy2
0

Answer:

0.125

Step-by-step explanation:

given that the digits are from 1 to 9, then the possible numbers are;

29, 98...... 2+9=11

38, 83......3+8=11

47, 74.......4+7=11

56, 65........5+6=11

the sample space is

S={ 29,98,38,83,47,74,56,65}

Whole numbers are divisible by 4  if the number formed by the last two digits if the number is evenly divisible by 4.

Of these numbers, the one that are divisible by 4 are

56

Therefore the probability that Rahul guessed a number that is divisible by 4 is

Prob= \frac{c(E)}{c(S)} \\\\Prob=\frac{1}{8}

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