Math, asked by renusingh48505, 1 year ago

Sachin invests rupees 8500 in 10% , rupees 100 shares at rupees 170. He sells the shares when the price of each share rose by rupees 30. He invests the proceeds in 12% rupees 100 shares at rupees 125. Find:
(I) the sale proceeds
(ii) the number of rupees 125 shares.
(iii) the change in annual income

Answers

Answered by rahulsugandh
6

Answer:

see the image

Step-by-step explanation:

Attachments:
Answered by MavisRee
27

Answer:

Sales proceeds =  Rs 10000

The number of Rs 125 shares = 80

Change in annual income = Rs 700

Step-by-step explanation:

Given,

Purchased price of 1 share = Rs. 170

Total he invested = Rs 8500

So,

Number of shares for Rs 8500 = 8500/170 = 50

Dividend = 10% of ( Number of shares * Price of each share )

Dividend = 10 % of ( 50 * 100 )

Dividend = Rs 500

Since,

He sold the shares when the price rose by Rs 30 ;

Selling price of each share = 170 + 30 = Rs 200

 Therefore,

( i ) Sales proceeds of selling 50 share :

= 200 × 50 = Rs. 10000

Hence,

Sales proceeds =  Rs 10000

 ( ii ) Number of new Rs.125 shares purchased :

= 10000 / 125 = 80

Hence,

The number of Rs 125 shares = 80

( iii ) Change in annual income  :

Dividend = 12 % of ( Number of Rs 125 shares * Price of each share )

Dividend = 12 % of ( 80 * 125 )

Dividend = Rs 1200

Change in income = 1200 - 500 = Rs 700

Hence,

Change in annual income = Rs 700

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