Sachin starts at 9:15a.m. from his home and reaches the school at 9:45a.m. . After the school , while returning, he starts at 4:00p.m. and reaches home at 4:15p.m. .The distance of his school from his home is 5 km. Calculate his average speed
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Answer:
Ans: 30 km
Let distance between house and office
=
x
km
Time taken if he moves with a speed of 30 km/hr
=
x
30
hr
Time taken if he moves with a speed of 40 km/hr
=
x
40
hr
Difference in time
=
x
30
−
x
40
But the difference in time = (10 min + 5 min) = 15 min =
1
4
hr
Therefore,x
30
−
x
40
=
1
4
4
x
−
3
x
=
30
x
=
30
Explanation:
product of speeds
difference of speeds
×
difference in time
30
×
40
10
×
15
60
=
30
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