Sachin takes 10 rounds of a rectangular park, 50 m long and 20 m wide. Find
the total distance covered by him.
Answers
Answer:
1 km and 400 meter.
Step-by-step explanation:
given length - 50 m
wide- 20 m
so, perimeter - 2(l+b)
2(50+20)
2*70
140 meter for one round
since he has taken 10 round so, total distance covered by him is 10 *140 meter
i.e, 1400 meter
equal to 1 km & 400 meter.
Given:
Sachin walks 10 rounds on a rectangular field of length 50 meters and breadth of 20 meters.
To Find:
The distance walked by Sachin after 10 rounds.
Solution:
1. The total distance covered by Sachin for 1 round will be equal to the perimeter of the rectangle.
2. Hence, the total distance covered by Sachin for 10 rounds will be,
=> Total distance covered by Sachin for 10 rounds = 10 x perimeter of the rectangle.
3. Perimeter of the rectangle is calculated using the formula,
=> Perimeter of a rectangle = 2 x ( length + breadth ),
4. Substitute the values of length and breadth in the above formula,
=> Perimeter of the rectangle = 2 x ( 50 + 20 ),
=> Perimeter of the rectangle = 2 x 70,
=> Perimeter of the rectangle = 140 meters.
5. Hence, the distance covered by Sachin per round is 140 meters,
=> Total distance covered by Sachin after 10 rounds = 140 x 10 = 1400 meters.
Therefore, the total distance covered by Sachin after 10 rounds is 1400 meters.