Question

Sachin walks 12 km towards East
and turns to his right and walks 8
km. Then he again took right turn
and walks 6 km. How far is Sachin
from the starting point ?​

Answer 1

Answer:

Sachin is 10km away from the initial point

Step-by-step explanation:

As you can see in the attachment that between initial point and final point a right triangle is formed with Perpendicular (AC)=8km, Base(CB)=6km (12-6=6) and to find the distance between the two points we need to find the Hypotenuse

By using Pythagoras Theorem

(Hypotenuse)^2=(Base)^2+(Perpendicular)^2

(AB)^2=(AC)^2+(CB)^2

(AB)^2=8^2+6^2

(AB)^2=64+36

(AB)^2=100

AB =√100

AB =10

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Regards

Samriddhi ✌