Math, asked by shashvanthsaravana2, 3 months ago

Sadhna is twice as old as Sita. If the sum of their ages is 48 years, how old is Sita?

Answers

Answered by kunaltaneja777pddzhn
4

let the age of Sita be x

the age of Sadhna will become 2x

sum of their age= 48

2x+x=48

3x=48

x=⁴⁸/3

x=16

let \: the \:age \: of \: sita \: be \: x \\ the \: age \:  of \: sadhna \: will \: become \: 2x \\  \\ sum \: of \: their \: age \:  = 48 \\  \\ \:x + 2x = 48 \\  \\ 3x  = 4 \\  \\ x =  \frac{48}{3}  \\  \\ x = 16

Answered by DüllStâr
43

Required Answer:

\Large{\boxed{\sf{Sita's\: age =16}}}

Question:

Sadhna is twice as old as Sita. If the sum of their ages is 48 years, how old is Sita?

To find?

How older is Sita

Given:

  • Sum of their ages = 48years
  • Sita was twice the age of Sandha

Let:

  • Sandha age be x
  • Sita age be 2x

Answer:

A/Q:

Sita age+Sandha age =48

.°. 2x + x =48

3x=48

x=48/3

x=16

So we value of x as 16

Now Let's put it's value to find age of Sita

Sita age x

Sita age =16

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