Math, asked by jawariyazainab17, 8 months ago

Safeer secured 35%marks and failed by 20marks and his friend raheel secured 45%marks and secured 20 more marks then the minimum to pass the examination find the percentage necessary to pass the exam ?

Answers

Answered by pernicious78
1

Step-by-step explanation:

Let the passing marks be x.

45% - 35% = (x + 20) - (x - 20)

10% = x + 20 - x + 20

10% = 40

Let the total marks be y.

10% of y = 40

(10/100) * y = 40

1/10 * y = 40

y/10 = 40

y = 400

Total marks = 400

Passing marks = 35% + 20

= 140

Or

35% + 20 = 45% - 20

35y/100 + 20 = 45y/100 - 20

35y/100 = 45y/100 - 20 - 20

35y/100 = 45y/100 - 40

35y/100 - 45y/100 = - 40

-10y/100 = - 40

10y/100 = 40

y = 40*100/10

y = 4000/10

y = 400

For passing marks the method provided above is same.

Answered by AbdulHaq02203011
0

Answer:

Step-by-step explanation:

No

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