Math, asked by vishal380, 1 year ago

sagar sold a tv to nitin at a lost of 20%.nitin sold it ptateek at a loss of 10% . if nitin paid Rs.16200 , what was sagar's C.P.?

Answers

Answered by jerri
1
hello Frnd

Let the Cost price for Sagar = X

He sold tv for 10% loss

Which means he sold it for
= X - X×20/100
= 0.8 X

Also Nitin sold if for 10% loss

Sales price of Nitin
= 0.8X - 0.8X × 10/100
= 0.72 X


● Now, Nitin paid 16200 to Sagar...

That means

16200 = 0.8X
X = 20,250


Hence Cost Price for Sagar is ₹ 20,250


hope it helps
jerri



Nagavamsi1: sorry, i dont think ur answer is correct
jerri: i solved as you said.. you can check my solution
Answered by Nagavamsi1
0
hi
First, we have to find out nitins cp.His cp is 16200. Nitins cp is Sagars Selling price. Sagars cp is (Loss/Selling price)+loss, which is 20/16200 + loss, 810+16200=17200.
Hope it helps you!
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