Sahil has ₹ 12 less than three times what Sohan has. If both have a total of ₹ 88 how many rupees each must have got? Solve the puzzle using the equations.
Answers
Answer:
Sohan has Rs 25
Sahil has = Rs 63
Step-by-step explanation:
Let say Say sohan has = Rs S
Sahil has Ra 12 less than three times what sohan has
Sahil has = 3S - 12
Sohan + Sahil = Rs 88
S + 3S - 12 = 88
=> 4S = 100
=> S = 25
Sohan has Rs 25
Sahil has = 3*25 - 12 = Rs 63
Answer:
The money possessed by Sohan is 25
The money possessed by Sahil is 63
Step-by-step Explanation:
We will write down the value in equation form and then solve it as follows:
Money that Sohan has= x
Money that Sahil has= 3x - 12
Now according to the question, sum of the money that they both has is equal to 88, So we can write it as follows:
(x) + (3x -12) = 88
= x + 3x = 88 +12
= 4x = 100
Thus x = 25
So the money possessed by Sohan is x = 25
The money possessed by Sahil is 3x – 12
=3(25) -12
= 75-12
=63