Question

Sahil jogs from one end A to the other end B on a straight 300 m road in 2 minute 30 seconds and then turns around and jogs 100 m back to point C in another I minute. What are Sahil’s average speed and velocity in jogging

1) from A to C

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Answer 1

Answer:

From point A to B

Distance covered= 300m Displacement= 300m

Time taken= 2 min 30 sec = (2 x 60) +30 = 150 sec

Average speed= Distance covered/Timetaken 300 150 - 2 m/sec

Average velocity= Displacement/Timetaken 300 150 = 2 m/sec

From point A to C

Distance covered= 300 + 100 = 400m

Displacement= 300 - 100 = 200m

Time taken= 3 min 30 sec = 30 = 210 sec = (3 x 60) + 30 = 210 sec

Average speed= Distance covered/Timetaken 400/210 = 1.90 m/sec

Average velocity= Displacement/Timetaken = 200/210 =

0.95 m/sec