Question

sahil room is a rectangle with a perimeter of 40 feet. the width of the room is 8 feet.what is the length of the room?

Answer 1

length L

perimeter = 2 * (L + 8 ) = 40
                       L + 8 = 20 feet
                      L =  12 feet

Answer 2

Perimeter = 40 ft
Width = 8 ft

P = 2 (l+w)
40 = 2(l+8)
20 = l+8
l = 20-8
l = 12 ft