Math, asked by mariyamehru, 2 months ago

sahil,s age is three times his son,s age ten years ago he was five times his son,s age. find their present ages.​

Answers

Answered by titisha13022006
0

Answer:

present age of Sahil's son = x

present age of Sahil = 3x

Step-by-step explanation:

let 3x−10=5(x−10)

3x-10=5x-50⇒3x−10=5x−50

3x-5x=-50+10⇒3x−5x=−50+10

=-2x=-40⇒ −2x=−40

x={-40}{-2}=20⇒x= -40/-2

 ​=20 years

hence present age of Sahil's son = x = 20

therefore present age of Sahil = 3x = 60

Answered by s18143
0

Answer:

Let Aman's son age =x

Aman's age =3x

Ten years ago, he was 5 times the age of his son.

Therefore, 3x−10=5(x−10)

3x−10=5x−50

2x=40

x=20

Aman's son is 20 yrs old

Aman is 3x=3×20=60 yrs old

pls mark it as brainliest

Similar questions