Question

Saketh's jogs from one end A to the other end B of a straight 300 m road in 2
minutes 30 seconds and then turns around and jogs 100 m back to point in
another 1 minute. What are Saketh's average speeds and velocities in jogging (a
from A to B and (b) from A to C?​

Answer 1

Explanation:

From pont A to B

Distance covered= 300m

Displacement= 300m

Time taken= 2 min 30 sec = (2 x 60) + 30 =

150 sec

Average speed= Distance covered

Timetaken

2 m/sec

Average velocity= Timetaken Displacement

2 m/sec

From point A to C

Distance covered= 300 + 100 = 400m

Displacement= 300 - 100 = 200m

Time taken= 3 min 30 sec = (3 x 60) + 30 =

210 sec

Average speed=

1.90 m/sec

Distance covered Timetaken 400 210

Average velocity= Displacement Timetaken 200 210

0.95 m/sec